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MCB 10 PSet 1 – For each of the following 4

MCB 10 PSet 1 – For each of the following 4 MCB 10 Problem Set 1 (15 Points Total) Fa 2016 Questions 1 to 4 (4 Points): For each of the following 4 pedigrees indicate which of thefollowing are possible modes of inheritance for the trait: (1) autosomal dominantinheritance; (2) autosomal recessive inheritance; (3) mitochondrial inheritance; (4) Xlinked recessive inheritance; (5) X-linked dominant inheritance. Note: more than onemode of inheritance may be possible for a given pedigree. Assume completepenetrance and no heteroplasmy.Pedigree 1 Pedigree 2 Pedigree 3 Pedigree 4 MCB 10 Problem Set 1 (15 Points Total) Fa 2016 Bambam and his father Fred both have two single locus autosomal dominant disorders:epsilon sclerosis and gamma dystrophy. The genes that cause the two disorders arelocated 7 cM apart on chromosome 12. Bambam’s mother Wilma is healthy (has neitherdisorder). Bambam marries Pebbles who is healthy (has neither disorder).Question 5 (2 Points): If Bambam and Pebbles have a child, what is the probability thatthe child has both epsilon sclerosis and gamma dystrophy? Question 6 (2 Points): If Bambam and Pebbles have a child, what is the probability thatthe child suffers from epsilon sclerosis but not gamma dystrophy? MCB 10 Problem Set 1 (15 Points Total) Fa 2016 In a study of 653 family trios (each consisting of a mother, father and child) the followingnumbers of recombinant chromosomes (among the 1306 chromosomes found in thechildren) were observed for two linked autosomal markers:mother recombinant31 father recombinant48 Question 7 (1 Point): estimate the fraction of recombinants Question 8 (1 Point): what is the distance between markers in units of centiMorgans(cM)? MCB 10 Problem Set 1 (15 Points Total) Fa 2016 Suppose that pattern baldness is caused by a single autosomal gene mutation that hasa dominant effect in males (either one or two copies of the mutation cause patternbaldness) and a recessive effect in females (two copies of the mutation cause patternbaldness). A second gene on a different autosomal chromosome affects hair color witha recessive mutation that results in light hair instead of dark hair. Mary has patternbaldness and light hair. Mary marries John who has no pattern baldness and dark hair.John’s mother has light hair.Question 9 (2 Points): If a son is born to the couple what is the probability that he haspattern baldness and light hair? Question 10 (2 Points): If a son is born to the couple what is the probability that he hasno pattern baldness and dark hair? Question 11 (1 Points): If a daughter is born to the couple what is the probability thatshe has no pattern baldness and dark hair?